document.write( "Question 1205725: So, my problem is this I solved it once and I got it wrong can you guys help me out?
\n" ); document.write( "8x-6y=-2
\n" ); document.write( "8x+5y=-13\r
\n" ); document.write( "\n" ); document.write( "I am supposed to use the elimination method and get an ordered pair and I am still confused.
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Algebra.Com's Answer #842723 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"8x-6y=-2\".....eq.1
\n" ); document.write( "\"8x%2B5y=-13\"....eq.2
\n" ); document.write( "-------------------------------subtract eq.2 from eq.1 to eliminate \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"8x-6y-%288x%2B5y%29=-2-%28-13%29\"\r
\n" ); document.write( "\n" ); document.write( "\"8x-6y-8x-5y=-2%2B13\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%288x%29-6y-cross%288x%29-5y=11\"\r
\n" ); document.write( "\n" ); document.write( "\"-6y-5y=11\"\r
\n" ); document.write( "\n" ); document.write( "\"-11y=11\"\r
\n" ); document.write( "\n" ); document.write( "\"y=11%2F-11\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-1\"\r
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\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"8x-6y=-2\".....eq.1, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"8x-6%28-1%29=-2\"\r
\n" ); document.write( "\n" ); document.write( "\"8x%2B6=-2\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=-2-6\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=-8\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-8%2F8\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-1\"\r
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