document.write( "Question 1205698: The perimeter of a rectangle is 84. The length is 14 more than the width. Find the width and length.\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 66. The length is 3 less than
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Algebra.Com's Answer #842679 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Two of the same example but just different assigned values\r
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\n" ); document.write( "\n" ); document.write( "p, the given perimeter
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\n" ); document.write( "w+k, length being some k more than the width\r
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\n" ); document.write( "\n" ); document.write( "\"w%2Bw%2Bk=p%2F2\" accounts for the given perimeter\r
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\n" ); document.write( "\n" ); document.write( "\"2w%2Bk=p%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"2w=p%2F2-k\"\r
\n" ); document.write( "\n" ); document.write( "\"w=p%2F4-k%2F2\"-----------substitute the given values and find width and length.\r
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\n" ); document.write( "\n" ); document.write( "The second example is only slightly different.
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\n" ); document.write( "\"w%2B5w-3=66%2F2\"
\n" ); document.write( "You can do the rest of this.
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