document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205650>Question 1205650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the sum of an infinite geometric series where a1  = 180, and the common ratio is r = 3∕4 ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #842585 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=842585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "a = 180 = first term<BR>\n" );
document.write( "r = 3/4 = 0.75 = common ratio\r<BR>\n" );
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document.write( "Since -1 < r < 1 is true when r = 0.75, we can use the infinite geometric sum formula shown below.<BR>\n" );
document.write( "S = a/(1 - r)<BR>\n" );
document.write( "S = 180/(1 - 0.75)<BR>\n" );
document.write( "S = 720\r<BR>\n" );
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document.write( "Answer: <font color=red>720</font><BR>\n" );
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