document.write( "Question 1205640: y = (3x) / (x + 2). \n" ); document.write( "
Algebra.Com's Answer #842574 by math_tutor2020(3816)\"\" \"About 
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\n" ); document.write( "It's not clear what your teacher wants here.
\n" ); document.write( "Please post the full instructions.\r
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\n" ); document.write( "\n" ); document.write( "Since you posted this in the \"inverses\" section, I'll assume you want to find the inverse.
\n" ); document.write( "To do so, we will swap x and y, and then solve for y.
\n" ); document.write( "y = (3x)/(x+2)
\n" ); document.write( "x = (3y)/(y+2)
\n" ); document.write( "x(y+2) = 3y
\n" ); document.write( "xy+2x = 3y
\n" ); document.write( "2x = 3y-xy
\n" ); document.write( "2x = y(3-x)
\n" ); document.write( "(2x)/(3-x) = y
\n" ); document.write( "y = (2x)/(3-x)\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the inverse of y = (3x)/(x+2) is y = (2x)/(3-x)\r
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\n" ); document.write( "\n" ); document.write( "y = (2x)/(3-x) is equivalent to y = (-2x)/(x-3) when we factor -1 out of the denominator.
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