document.write( "Question 1205634: log base 4 of y + log base2 of y =12\r
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Algebra.Com's Answer #842557 by ikleyn(52909)\"\" \"About 
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document.write( "Your starting equation is\r\n" );
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document.write( "    \"log%284%2C%28y%29%29\" + \"log%282%2C%28y%29%29\" = 12.    (1)\r\n" );
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document.write( "Use the base change formula\r\n" );
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document.write( "    \"log%282%2C%28y%29%29\" = \"log%284%2C%28y%29%29%2Flog%284%2C%282%29%29\" = \"log%284%2C%28y%29%29%2F%28%281%2F2%29%29\" = \"2%2Alog%284%2C%28y%29%29\".\r\n" );
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document.write( "Therefore, equation (1) takes the form\r\n" );
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document.write( "    \"log%284%2C%28y%29%29\" + \"2%2Alog%284%2C%28y%29%29\" = 12\r\n" );
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document.write( "    \"3%2Alog%284%2C%28y%29%29\" = 12\r\n" );
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document.write( "    \"log%284%2C%28y%29%29\" = 12/3 = 4\r\n" );
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document.write( "    y = \"4%5E4\" = 256.\r\n" );
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document.write( "ANSWER.  y = 256.\r\n" );
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\n" ); document.write( "\n" ); document.write( "On logarithms and their properties,  see these introductory lessons\r
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