document.write( "Question 1205594: What is the 15 terms of the arithmetic progression whose first term is 6and common difference is 7
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Algebra.Com's Answer #842493 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "the arithmetic progression general formula is \r
\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D=a%5B1%5D%2Bd%28n-1%29\"\r
\n" ); document.write( "\n" ); document.write( "given that \"a%5B1%5D=6\" and \"d=7\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5Bn%5D=6%2B7%28n-1%29\"\r
\n" ); document.write( "\n" ); document.write( "now find the \"15\" terms\r
\n" ); document.write( "\n" ); document.write( "we know first term, so second term is\r
\n" ); document.write( "\n" ); document.write( "\"n=2\"
\n" ); document.write( "\"a%5B2%5D=6%2B7%282-1%29=13\"\r
\n" ); document.write( "\n" ); document.write( "third term will be\r
\n" ); document.write( "\n" ); document.write( "\"n=3\"
\n" ); document.write( "\"a%5B3%5D=6%2B7%283-1%29=6%2B14=20\"\r
\n" ); document.write( "\n" ); document.write( "or simply find the next term by adding common difference to previous term\r
\n" ); document.write( "\n" ); document.write( "\"a%5B4%5D=27\"
\n" ); document.write( "\"a%5B5%5D=34\"
\n" ); document.write( "\"a%5B6%5D=41\"
\n" ); document.write( "\"a%5B7%5D=48\"
\n" ); document.write( "\"a%5B8%5D=55\"
\n" ); document.write( "\"a%5B9%5D=62\"
\n" ); document.write( "\"a%5B10%5D=69\"
\n" ); document.write( "\"a%5B11%5D=76\"
\n" ); document.write( "\"a%5B12%5D=83\"
\n" ); document.write( "\"a%5B13%5D=90\"
\n" ); document.write( "\"a%5B14%5D=97\"
\n" ); document.write( "\"a%5B15%5D=104\"\r
\n" ); document.write( "\n" ); document.write( "so, first \"15\" terms are:
\n" ); document.write( "\"6\",\"13\",\"20\",\"27\",\"34\",\"41\",\"48\",\"55\",\"62\",\"69\",\"76\",\"83\",\"90\",\"97\",\"104\"\r
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