document.write( "Question 1205576: A 20.80 gift box of candy contains 2 varieties. One type costs 1.60/kg and the other costs $1.80/kg. The number of kg at 1.80 is twice the number of kg as $1.60. Find the number of kg of each type of candy. \n" ); document.write( "
Algebra.Com's Answer #842479 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "For new tutor CharcoalRobin....

\n" ); document.write( "(1) Learn how to use html to make your posts readable. Your post with the whole solution in a single paragraph is extremely hard to read.

\n" ); document.write( "You can learn some of the basics by looking at the responses from other tutors and clicking on \"show source\".

\n" ); document.write( "(2) Check you work and your answer before submitting your response. We are all capable of making arithmetic errors....

\n" ); document.write( "Here is an informal mental solution that solves the problem by the same path as the formal algebraic solution shown by tutor @ikleyn.

\n" ); document.write( "Since there are twice as many of the candies at $1.80/kg as there are at $1.60/kg, make groups of 2kg at $1.80/kg and 1kg at $1.60/kg, costing a total of 2($1.80)+$1.60 = $5.20.

\n" ); document.write( "Since the total cost is $20.80, the number of these groups is $20.80/$5.20 = 4.

\n" ); document.write( "So there are 4*2 = 8kg of candies at $1.80/kg and 4kg at $1.60/kg.

\n" ); document.write( "ANSWER: 8kg at $1.80/kg and 4kg at $1.60/kg

\n" ); document.write( "CHECK: 8($1.80)+4($1.60) = $14.40+$6.40 = $20.80

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