document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205576>Question 1205576</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 20.80 gift box of candy contains 2 varieties. One type costs 1.60/kg and the other costs $1.80/kg. The number of kg at 1.80 is twice the number of kg as $1.60. Find the number of kg of each type of candy. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #842474 by </B><A HREF=/tutors/aboutme.mpl?userid=CharcoalRobin><B>CharcoalRobin(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharcoalRobin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=842474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Variety Type 1, T1 which is $1.60/kg, and Variety Type 2, T2 which is $1.80/kg, Since we know there are two types of varieties that the gift box contains, for the first equation, we can sum the two Types together with their respective prices for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281.60%29T1+%2B+%281.80%29T2+=+20.80 ALIGN=MIDDLE  ALT=\"%281.60%29T1+%2B+%281.80%29T2+=+20.80\"   DISABLED_style= \"max-width:90%; height:auto;\" > (i.e. the cost of the gift box). The second equation can be found from the relation that Variety Type 2 is \"twice the number\" as Variety Type 1, therefore the second equation would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28T2%29+=+2%28T1%29 ALIGN=MIDDLE  ALT=\"%28T2%29+=+2%28T1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where T1 and T2 are variables corresponding to their respective prices.  Since we know that T2 = 2T1, we can substitute in for T2 for the first equation, using the second.  So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281.60%29T1+%2B+%281.80%29%282T1%29+=+20.80 ALIGN=MIDDLE  ALT=\"%281.60%29T1+%2B+%281.80%29%282T1%29+=+20.80\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Then, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281.60%29T1+%2B+%283.40%29%28T1%29+=+20.80 ALIGN=MIDDLE  ALT=\"%281.60%29T1+%2B+%283.40%29%28T1%29+=+20.80\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Combining Like Terms, and we have <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5T1+=+20.80 ALIGN=MIDDLE  ALT=\"5T1+=+20.80\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Hence, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T1+=+4.20 ALIGN=MIDDLE  ALT=\"T1+=+4.20\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now we can either substitute our value of T1 in for the first or second equation, but it will be easier to substitute T1 into the second equation, as there are less steps needed to take in order to evaluate what T2 is.  Solving for T2, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T2+=+2%284.20%29 ALIGN=MIDDLE  ALT=\"T2+=+2%284.20%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and finally, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=T2+=+8.40 ALIGN=MIDDLE  ALT=\"T2+=+8.40\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now that we have solved for T1 and T2, we now know the respective amount of weight of each Type of Variety. In other words, T1 represents the \"number of kg\" of the first Type of candy, whereas T2 represents the \"number of kg\" of the second Type of candy.     </SPAN>\n" );
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