document.write( "Question 1205551: Hi
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document.write( "5 years ago David was twice as old as Laura. Next year Laura will be 3/5 the age of David. How old are each of them.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #842439 by greenestamps(13216) You can put this solution on YOUR website! \n" ); document.write( "There are always many different ways to set up a problem for solving using formal algebra. You should always be comfortable with trying different ways, to find a way for which the effort required to solve the problem is as little as possible. \n" ); document.write( "Often, if part of the given information is that one number is n times another, an easy path to the solution is by starting with that information. Try that on this problem.... \n" ); document.write( "Let x = Laura's age 5 years ago \n" ); document.write( "Then 2x = David's age 5 years ago \n" ); document.write( "\"Next year\" is 6 years after \"5 years ago\", so their ages next year will be x+6 and 2x+6. Laura's age will be 3/5 of David's age then: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWERS: Their current ages are \n" ); document.write( "Laura = x+5 = 12+5 = 17 \n" ); document.write( "David = 2x+5 = 2(12)+5 = 24+5 = 29 \n" ); document.write( "---------------------------------------------------------- \n" ); document.write( "Language note.... \n" ); document.write( "\"each\" refers to a single thing -- in this case a single person. So \n" ); document.write( "\"How old are they?\" \n" ); document.write( "or \n" ); document.write( "\"How old is each of them?\" \n" ); document.write( "but not \n" ); document.write( "\"How old are each of them?\" \n" ); document.write( " \n" ); document.write( " |