document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205527>Question 1205527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A helicopter leaves a point P and flies on a bearing of 162 for 3km to a point Q, and then due west to a point R which is on a bearing of 220 from P. Find PR. Find RQ. The flight takes 4 minutes . Find the speed of the helicopter in kilometer per hour  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #842389 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=842389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i get:\r<BR>\n" );
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document.write( "PR = 3.724548327 kilometers<BR>\n" );
document.write( "RQ = 3.321144499 kilometers.\r<BR>\n" );
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document.write( "total trip from P to Q to R = 6.321144499 kilometers.<BR>\n" );
document.write( "that took 4 minutes = 4/60 hours.<BR>\n" );
document.write( "rate * time = distance.<BR>\n" );
document.write( "rate * 4/60 = 6.321144499.<BR>\n" );
document.write( "solve for rate to get:<BR>\n" );
document.write( "rate = 6.321144499 * 60 / 4 = 94.81716749 kilometers per hour.   \r<BR>\n" );
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document.write( "my diagram is shown below along with my scribbles.\r<BR>\n" );
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document.write( "the locations were from P to Q to R.<BR>\n" );
document.write( "that would be line segments PQ and RQ.\r<BR>\n" );
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document.write( "line segment RQ is composed of line segments RC and CQ.\r<BR>\n" );
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document.write( "triangles PQC and PRC were formed.<BR>\n" );
document.write( "angle QPC is 18 degrees because it is 180 minus 162.<BR>\n" );
document.write( "162 degrees was the bearing from point P to point Q.\r<BR>\n" );
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document.write( "angle RPC is 40 degrees because it is 220 minus 180.<BR>\n" );
document.write( "220 degrees was the bearing from point P to point R.\r<BR>\n" );
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document.write( "i used storage locations to hold the results from the various calculations required.\r<BR>\n" );
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document.write( "the length of PQ was given as 3 kilometers.<BR>\n" );
document.write( "the length of CQ was based on the sine of 18 degrees and was equal to .92705... kilometers that were stored in SLA.<BR>\n" );
document.write( "SLA is storage location A on my calculator.\r<BR>\n" );
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document.write( "the length of PC was based on the cosine of 18 degrees and was equal to 2.85316... that were stored in SLB.<BR>\n" );
document.write( "SLB is storage location B on my calculator.\r<BR>\n" );
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document.write( "since i found the length of PC, i was able to use that to get the lengths of PR and RC.<BR>\n" );
document.write( "RC was 2.39409... and stored in SLC.<BR>\n" );
document.write( "PR was 3.72454... and stored in SLD.\r<BR>\n" );
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document.write( "RQ was the sum of RC and CQ equal to 3.32114... and stored in SLE.\r<BR>\n" );
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document.write( "the total route traveled by the helicopter was the length of PQ and QC and RC which was equal to 6.32114... and stored in SLF.\r<BR>\n" );
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document.write( "to find the speed of the helicopter, i used the rate * time = distance formula.<BR>\n" );
document.write( "the time was 4 minutes = 4/60 hours.<BR>\n" );
document.write( "the distance was 6.32114.... which was stored in SLF.<BR>\n" );
document.write( "the formual because rate * 4/60 = 6.32114...<BR>\n" );
document.write( "i solved for rate to get rate = 94.817... kilometers per hour which was stored in SLG.\r<BR>\n" );
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document.write( "hopefully, you can follow this.<BR>\n" );
document.write( "if you have any questions, feel free to send me an email through algebra.com.<BR>\n" );
document.write( "theo </SPAN>\n" );
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