document.write( "Question 1205508: If you solve the question below, I'll be appreciated.\r
\n" ); document.write( "\n" ); document.write( "A statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 24 and computed the sample mean to be 98.\r
\n" ); document.write( "\n" ); document.write( "Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.\r
\n" ); document.write( "\n" ); document.write( "A. Estimate the population mean with 95% confidence.\r
\n" ); document.write( "\n" ); document.write( "Confidence Interval = ?\r
\n" ); document.write( "\n" ); document.write( "B. Estimate the population mean with 95% confidence, changing the population standard deviation to 49;\r
\n" ); document.write( "\n" ); document.write( "Confidence Interval = ?\r
\n" ); document.write( "\n" ); document.write( "C. Estimate the population mean with 95% confidence, changing the population standard deviation to 6;\r
\n" ); document.write( "\n" ); document.write( "Confidence Interval = ?
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Algebra.Com's Answer #842372 by Theo(13342)\"\" \"About 
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A statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 24 and computed the sample mean to be 98.
\n" ); document.write( "Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.\r
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\n" ); document.write( "\n" ); document.write( "since the standard deviation is taken from the population, the z-score is used.\r
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\n" ); document.write( "\n" ); document.write( "A. Estimate the population mean with 95% confidence.\r
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\n" ); document.write( "\n" ); document.write( "critical z-score for two tailed 95% confidence interval is z = plus or minus 1.96.\r
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\n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m)/s
\n" ); document.write( "z is the critical z-score.
\n" ); document.write( "x is the critical raw score
\n" ); document.write( "m is the population mean
\n" ); document.write( "s is the standard error when you're looking for the mean of a sample.\r
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\n" ); document.write( "\n" ); document.write( "sample size is 48.\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / sqrt(sample size) = 24 / sqrt(48) = 3.4641 rounded to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "on the high side of the confidence interval, z = (x-m)/s becomes 1.96 = (x-98)/3.4641.
\n" ); document.write( "solve for x to get x = 1.96 * 3.4641 + 98 = 104.79 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "on the low side of the confidence interval, z = (x-m)/s becomes -1.96 = (x-98)/3.4641.
\n" ); document.write( "solve for x to get x = -1.96 * 3.4641 + 98 = 91.21 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "your 95% confidence limit is equal to (91.21,104.79).\r
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\n" ); document.write( "\n" ); document.write( "B. Estimate the population mean with 95% confidence, changing the population standard deviation to 49;\r
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\n" ); document.write( "\n" ); document.write( "population standard deviation = 49\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / sqrt(sample size) = 49 / sqrt(48) = 7.0725 rounded to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "critical z-score for two tailed 95% confidence interval is z = plus or minus 1.96.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the high side of the confidence interval, z-score formula becomes 1.96 = (x-98)/7.0725.
\n" ); document.write( "solve for x to get x = 1.96 * 7.0725 + 98 = 111.86 rounded to 2 decimal places.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the low side of the confidence interval, z-score formula becomes -1.96 = (x-98)/7.0725.
\n" ); document.write( "solve for x to get x = -1.96 * 7.0725 + 98 = 84.14 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "your 95% confidence limit is equal to (84.14,111.86).\r
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\n" ); document.write( "\n" ); document.write( "C. Estimate the population mean with 95% confidence, changing the population standard deviation to 6;\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "critical z-score for two tailed 95% confidence interval is z = plus or minus 1.96.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / sqrt(ample size) = 6 / sqrt(48) = .8660 rounded to 4 decimal places.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the high side of the confidence interval, z-score formula becomes 1.96 = (x-98)/.8660.
\n" ); document.write( "solve for x to get x = 1.96 * .8660 + 98 = 99.70 rounded to 2 decimal places.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "on the low side of the confidence interval, z-score formula becomes -1.96 = (x-98)/.8660.
\n" ); document.write( "solve for x to get x = -1.96 * .8660 + 98 = 96.30 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "your 95% confidence interval is equal to (96.30,99.70).\r
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