document.write( "Question 1205510: A box contains 10 chocolates, of which 4 are dark chocolates and 6 are milk chocolates. If two chocolates are randomly selected without replacement, what is the probability of getting one dark chocolate and one milk chocolate in any order? \n" ); document.write( "
Algebra.Com's Answer #842362 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "A box contains 10 chocolates, of which 4 are dark chocolates and 6 are milk chocolates.
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document.write( "The number of all possible different pairs without looking the order \r\n" );
document.write( "is the number of combinations of 10 items taken 2 at a time \r\n" );
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document.write( "    total = \"C%5B10%5D%5E2\"= \"%2810%2A9%29%2F2\" = 5*9 = 45.\r\n" );
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document.write( "The number of pairs (dark,milk), in this order, is 4*6 = 24;\r\n" );
document.write( "the number of pairs (milk,dark), in this order, is 6*4 = 24;\r\n" );
document.write( "but since the order does not matter, we DO NOT ADD 24 + 24 - we simply take/keep the value of 24\r\n" );
document.write( "for all possible different pairs (dark,milk) or (milk,dark) of favorable pairs\r\n" );
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document.write( "    favorable = 6*4 = 24.\r\n" );
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document.write( "The probability under the problem's question is\r\n" );
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document.write( "    P = \"favorable%2Ftotal\" = \"24%2F45\" = \"8%2F15\".    ANSWER\r\n" );
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