document.write( "Question 1205498: Determine the equation of the tangent line to the curve 𝑦 = −𝑥
\n" ); document.write( "2 − 3𝑥 + 4 at 𝑥 = 2.
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Algebra.Com's Answer #842353 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the equation of the tangent line to the curve \r
\n" ); document.write( "\n" ); document.write( "\"y+=+-x%5E2-+3x+%2B+4\" at \"x=+2\"\r
\n" ); document.write( "\n" ); document.write( " The gradient of the tangent is equal to the derivative of the curve evaluated at the point where the curve and tangent line meet.\r
\n" ); document.write( "\n" ); document.write( "at \"x=+2\" , \"y+=+-2%5E2-+3%2A2+%2B+4=-4-6%2B4=-6\"\r
\n" ); document.write( "\n" ); document.write( "point of tangency is at (\"2\",\"-6\")\r
\n" ); document.write( "\n" ); document.write( "\"y\"’ =\"+-2x-+3\"\r
\n" ); document.write( "\n" ); document.write( "compute the value of the derivative function at \"x=2\"\r
\n" ); document.write( "\n" ); document.write( "\"y\"'\"%282%29=-2%2A2-3=-7\"\r
\n" ); document.write( "\n" ); document.write( "so, slope is \"m=-7\"\r
\n" ); document.write( "\n" ); document.write( "use the point-slope formula of a line, substitute the values above\r
\n" ); document.write( "\n" ); document.write( "\"y-y1=m%28x-x1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-%28-6%29=-7%28x-2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B6=-7x%2B14\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-7x%2B14-6\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-7x%2B8\"=> tangent line\r
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