document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205495>Question 1205495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Janet is presently one-sixth as old as her<BR>\n" );
document.write( "mother. Her mother’s age, when divided<BR>\n" );
document.write( "by 2, 3, 4, 6, or 8, always leaves one<BR>\n" );
document.write( "remaining year. This is not so when her<BR>\n" );
document.write( "mother’s present age is divided by 5, for<BR>\n" );
document.write( "then there is nothing left over. How old<BR>\n" );
document.write( "is Janet’s mother?<BR>\n" );
document.write( "How old is Janet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #842346 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=842346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m = 25<BR>\n" );
document.write( "25 = 2 * 12 + 1<BR>\n" );
document.write( "25 = 3 * 8 + 1<BR>\n" );
document.write( "25 = 4 * 6 + 1<BR>\n" );
document.write( "25 = 6 * 4 + 1<BR>\n" );
document.write( "25 = 8 * 3 + 1<BR>\n" );
document.write( "25 = 5 * 5 + 0<BR>\n" );
document.write( "her present age is 25.\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );