document.write( "Question 1205494: The speed of light is 300,000km/sec and the planet Pluto is located at a distance of 6 billion km from Earth. If a spaceship, traveling at a constant speed in a straight line, goes from Earth to Pluto in 100 hours, at what fraction of the speed of light is this spaceship travelling? Thank You!
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Algebra.Com's Answer #842343 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "300,000 = 3*10^5 \n" ); document.write( "6 billion = 6*10^9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 hour = 60*60 = 3600 seconds \n" ); document.write( "100 hours = 100*3600 = 360,000 seconds \n" ); document.write( "360,000 = 3.6*10^5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Determine the speed of the spaceship \n" ); document.write( "distance = rate*time \n" ); document.write( "rate = distance/time \n" ); document.write( "rate = (6*10^9 km)/(3.6*10^5 seconds) \n" ); document.write( "rate = (6/3.6)*((10^9)/(10^5)) km per second \n" ); document.write( "rate = (60/36)*10^4 km per second \n" ); document.write( "rate = (5/3)*10^4 km per second\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide this over the speed of light to wrap things up \n" ); document.write( "( spaceship's speed )/( speed of light ) \n" ); document.write( "( (5/3)*10^4 )/( 3*10^5 ) \n" ); document.write( "( (5/3)*10^4 )/( 3*10*10^4 ) \n" ); document.write( "( (5/3)*10^4 )/( 30*10^4 ) \n" ); document.write( "( (5/3)/30 )*((10^4)/(10^4)) \n" ); document.write( "(5/3)/30 \n" ); document.write( "(5/3)*(1/30) \n" ); document.write( "5/90 \n" ); document.write( "1/18 is the final answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another approach\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's see how long it takes a light beam to go from Earth to Pluto \n" ); document.write( "distance = rate*time \n" ); document.write( "time = distance/rate \n" ); document.write( "time = (6*10^9 km)/(3*10^5 km per sec) \n" ); document.write( "time = (6/3)*((10^9)/(10^5)) sec \n" ); document.write( "time = 2*10^4 sec \n" ); document.write( "time = 20,000 sec\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide this over 360,000 seconds (the time it takes the spaceship to reach Pluto) and you should get the fraction 1/18 \n" ); document.write( "It represents the idea that the light beam can travel to Pluto 18 times in the same timespan the spaceship travels. \n" ); document.write( "In other words, the light beam travels 18/2 = 9 round trips from Earth to Pluto, and back. In these 9 round trips of the light beam, the spaceship will arrive at Pluto.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 1/18 \n" ); document.write( " \n" ); document.write( " |