document.write( "Question 1205492: Write 3x^2 - 12x = 1 - y in quadratic function standard form,
\n" ); document.write( "y = mx^2 + bx + c \n" ); document.write( "
Algebra.Com's Answer #842338 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Standard form is y = ax^2 + bx + c\r
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\n" ); document.write( "\n" ); document.write( "We need to move the 1 on the right hand side to the left side.
\n" ); document.write( "3x^2 - 12x = 1 - y
\n" ); document.write( "3x^2 - 12x - 1 = -y
\n" ); document.write( "-y = 3x^2 - 12x - 1 \r
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\n" ); document.write( "\n" ); document.write( "Then multiply everything by -1 to change the -y to y
\n" ); document.write( "-y = 3x^2 - 12x - 1
\n" ); document.write( "-1(-y) = -1(3x^2 - 12x - 1)
\n" ); document.write( "y = -3x^2 + 12x + 1 is the final answer.\r
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\n" ); document.write( "\n" ); document.write( "The quadratic is now in standard form y = ax^2 + bx + c
\n" ); document.write( "a = -3
\n" ); document.write( "b = 12
\n" ); document.write( "c = 1\r
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\n" ); document.write( "\n" ); document.write( "Standard form is useful if you want to apply the quadratic formula (as one example).
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