document.write( "Question 1205471: Twenty percent of the employees of a large company are female. Use the normal approximation
\n" ); document.write( "of the binomial probabilities to answer the following questions. What is the probability
\n" ); document.write( "that in a random sample of 80 employees
\n" ); document.write( "a. exactly 16 will be female?
\n" ); document.write( "b. 14 or more will be female?
\n" ); document.write( "c. 15 or fewer will be female?
\n" ); document.write( "d. 18 or more will be female
\n" ); document.write( "e. exactly 17 will be female?
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Algebra.Com's Answer #842297 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Check out this article
\n" ); document.write( "https://www.statology.org/normal-approximation/\r
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\n" ); document.write( "\n" ); document.write( "If you're still stuck then move to the next section shown below.\r
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\n" ); document.write( "\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "n = sample size = 80
\n" ); document.write( "p = probability of selecting a woman = 0.20\r
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\n" ); document.write( "\n" ); document.write( "Computing \"np\" and \"n%281-p%29\" leads to 16 and 64 respectively.
\n" ); document.write( "Both results are larger than 5, so they meet the criteria \"np+%3E=+5\" and \"n%281-p%29+%3E=+5\"
\n" ); document.write( "Some stats textbooks will use 10 in place of 5; luckily 16 and 64 meet that threshold as well.
\n" ); document.write( "We confirm that a normal approximation to the binomial can be used.
\n" ); document.write( "Make sure to do this check before going any further. \r
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\n" ); document.write( "\n" ); document.write( "mu = mean
\n" ); document.write( "sigma = standard deviation\r
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\n" ); document.write( "\n" ); document.write( "mu = n*p
\n" ); document.write( "mu = 80*0.20
\n" ); document.write( "mu = 16\r
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\n" ); document.write( "\n" ); document.write( "sigma = sqrt(n*p*(1-p))
\n" ); document.write( "sigma = sqrt(80*0.20*(1-0.20))
\n" ); document.write( "sigma = 3.577708764 approximately\r
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\n" ); document.write( "\n" ); document.write( "Refer to the link I posted to account for the continuity correction. This is where we go from a discrete setting to a continuous setting.\r
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\n" ); document.write( "\n" ); document.write( "x = 16 leads to the interval 15.5 < x < 16.5\r
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\n" ); document.write( "\n" ); document.write( "Use any stats calculator you want to find the area under the normal distribution curve between those endpoints.
\n" ); document.write( "I'll use a TI84.\r
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\n" ); document.write( "\n" ); document.write( "If you are using that as well then press the button labeled \"2nd\".
\n" ); document.write( "Then press the VARS key.
\n" ); document.write( "Move to normalCDF\r
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\n" ); document.write( "\n" ); document.write( "The full command to type in would be normalCDF(15.5, 16.5, 16, 3.577708764)
\n" ); document.write( "The standard template is normalCDF(L, R, mu, sigma)
\n" ); document.write( "L = left endpoint
\n" ); document.write( "R = right endpoint\r
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\n" ); document.write( "\n" ); document.write( "The result of the calculation normalCDF(15.5, 16.5, 16, 3.577708764) is approximately 0.11114589
\n" ); document.write( "Round that value however needed.\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "P(15.5 < x < 16.5) = 0.11114589 approximately.\r
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\n" ); document.write( "\n" ); document.write( "There's about an 11.1146% chance of having 16 women in the sample of 80 employees.\r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "\"14 or more\" translates to \"x+%3E=+14\"\r
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\n" ); document.write( "\n" ); document.write( "Revisit the continuity correction chart in this link
\n" ); document.write( "https://www.statology.org/normal-approximation/\r
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\n" ); document.write( "\n" ); document.write( "Apply the continuity correction to make \"x+%3E=+14\" convert to x > 13.5
\n" ); document.write( "We subtract off 0.5 from 14 to get this new endpoint.\r
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\n" ); document.write( "\n" ); document.write( "Using the TI84 we could type in
\n" ); document.write( "normalCDF(13.5, 9999, 16, 3.577708764)
\n" ); document.write( "Notice there technically isn't a right endpoint.
\n" ); document.write( "The 9999 is some really large number to effectively stand in for positive infinity.\r
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\n" ); document.write( "\n" ); document.write( "The TI84 calculator says the result is roughly 0.75765257\r
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\n" ); document.write( "\n" ); document.write( "Another calculator you could use is this
\n" ); document.write( "https://davidmlane.com/normal.html
\n" ); document.write( "It offers a diagram to go along with the area value.\r
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\n" ); document.write( "\n" ); document.write( "Another alternative is the Normal command in GeoGebra.
\n" ); document.write( "Or you could use the normDist command in a spreadsheet.
\n" ); document.write( "There are many other calculators that provide the same functionality.\r
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\n" ); document.write( "\n" ); document.write( "If your teacher wants you to use a Z table instead of a calculator, then be sure to follow those instructions. You'll need to convert to a z score first before using the table.
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\n" ); document.write( "\n" ); document.write( "Part (c)\r
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\n" ); document.write( "\n" ); document.write( "Use the continuity correction chart to go from \"x+%3C=+15\" to x < 15.5\r
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\n" ); document.write( "\n" ); document.write( "Whichever calculator or table you end up using, the answer should be approximately 0.44442708
\n" ); document.write( "The answer may slightly vary depending on what method you used.\r
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\n" ); document.write( "\n" ); document.write( "I'll leave the other parts for the student to do.
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