document.write( "Question 1205465: User
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document.write( "A small regional carrier accepted 16 reservations for a particular flight with 14 seats. 10 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 47% chance, independently of each other.
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document.write( "(Report answers accurate to 4 decimal places.)\r
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document.write( "Find the probability that overbooking occurs.
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document.write( "Find the probability that the flight has empty seats\r
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Algebra.Com's Answer #842288 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "A similar question has been asked before. \n" ); document.write( "Check out this link \n" ); document.write( "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1204038.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you're still stuck, then read on.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 14 seats. Ten of which are locked in for those guaranteed to show up for the flight. \n" ); document.write( "There are 14-10 = 4 seats left and 16-10 = 6 extra people competing for those remaining seats. \n" ); document.write( "These 6 extra people may or may not show up on time. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n = 6 = sample size \n" ); document.write( "p = 0.47 = probability a person arrives on time \n" ); document.write( "x = number extra people who arrive on time \n" ); document.write( "x is equal to a value from the set {0,1,2,3,4,5,6} \n" ); document.write( "x = 2 for instance means 2 extra people arrived on time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Random variable X follows a binonimal distribution because of these 3 reasons:
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B(x) = binomial probability \n" ); document.write( "B(x) = (nCx)*(p^x)*(1-p)^(n-x) \n" ); document.write( "The nCx refers to the nCr combination formula. Such values can be found in Pascal's Triangle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in the values mentioned for n and p \n" ); document.write( "We'll go from this \n" ); document.write( "B(x) = (nCx)*(p^x)*(1-p)^(n-x) \n" ); document.write( "to this \n" ); document.write( "B(x) = (6Cx)*(0.47^x)*(0.53)^(6-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then let's plug in x = 0 \n" ); document.write( "B(x) = (6Cx)*(0.47^x)*(0.53)^(6-x) \n" ); document.write( "B(0) = (6C0)*(0.47^0)*(0.53)^(6-0) \n" ); document.write( "B(0) = (1)*(0.47^0)*(0.53)^(6-0) \n" ); document.write( "B(0) = 0.022164361129 \n" ); document.write( "B(0) = 0.0222 \n" ); document.write( "This is the approximate probability of having 0 extra people show up.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could repeat similar steps for x = 1 through x = 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A quicker way is to use a spreadsheet. Specifically you'll use the binomDist function. \n" ); document.write( "Then use the round function to do as you'd expect. \n" ); document.write( "Example: \n" ); document.write( "=Round(A1,4) will round the value at cell A1 to 4 decimal places. Don't forget about the equal sign up front. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's the binomial probability distribution \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Overbooking happens when x = 5 or x = 6 extra people show up on time. \n" ); document.write( "B(5) + B(6) = 0.0729+0.0108 \n" ); document.write( "B(5) + B(6) = 0.0837 is the approximate probability of overbooking. \n" ); document.write( "This is roughly a 8.37% chance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Empty seats happen when x = 0 through x = 3, i.e when x < 4. \n" ); document.write( "B(0)+B(1)+B(2)+B(3) = 0.0222+0.1179+0.2615+0.3091 \n" ); document.write( "B(0)+B(1)+B(2)+B(3) = 0.7107 \n" ); document.write( "There's roughly a 71.07% chance of the flight having one or more empty seats.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------- \n" ); document.write( "----------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Probability that overbooking occurs: 0.0837 \n" ); document.write( "Probability that the flight has empty seats: 0.7107 \n" ); document.write( " \n" ); document.write( " |