document.write( "Question 1205166: Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. Find the value of quartile 3. (Round to the nearest whole number.) \n" ); document.write( "
Algebra.Com's Answer #842283 by Theo(13342)\"\" \"About 
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mean is 63.6
\n" ); document.write( "standard deviation is 2.5\r
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\n" ); document.write( "\n" ); document.write( "at quartile 3, 75% of the values are less than that.\r
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\n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m)/s\r
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\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw mean
\n" ); document.write( "s is the stqandard deviation\r
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\n" ); document.write( "\n" ); document.write( "formula becomes z = (x - 63.6) / 2.5\r
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\n" ); document.write( "\n" ); document.write( "z-score with 75% of the area under the normal distribution curve to the left of it is equal to .67449 rounded to 5 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "when z = that, z-score formula becomes .67449 = (x - 63.6) / 2.5
\n" ); document.write( "solve for x to get x = 2.5 * .67449 + 63.6 = 65.286225.
\n" ); document.write( "round to 2 decimal places to get 65.29.\r
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\n" ); document.write( "\n" ); document.write( "65.29 is the score that is at the 75th percentile of the data set which is at quartile 3.\r
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\n" ); document.write( "\n" ); document.write( "here's what it looks like on a normal distribution calculator.
\n" ); document.write( "first display is with z-scores.
\n" ); document.write( "second display is with raw scores.\r
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