document.write( "Question 1204904: A genetic experiment involving peas yielded one sample of offspring consisting of 433 green peas and 166 yellow peas. Use a 0.01 significance level to test the claim that under the same​ circumstances, 26​% of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution. \n" ); document.write( "
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sample size = 433 + 166 = 599
\n" ); document.write( "green peas = 433
\n" ); document.write( "yellow peas = 166\r
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\n" ); document.write( "\n" ); document.write( "p = .2771285476
\n" ); document.write( "q = 1-p = .7228714524\r
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\n" ); document.write( "\n" ); document.write( "mean = p
\n" ); document.write( "standard error = sqrt(p*q/n) = .018287644
\n" ); document.write( "n = sample size\r
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\n" ); document.write( "\n" ); document.write( "z = (x-m)/s is the formula used.
\n" ); document.write( "z is the critical z-score at 99% two tail confidence level.
\n" ); document.write( "x is the test mean of .26
\n" ); document.write( "m is the sample mean of p
\n" ); document.write( "s is the standard error\r
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\n" ); document.write( "\n" ); document.write( "critical z-score at 99% two tail confidence interval = plus or minus 2.5758 rounded to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "formula to find the test z-score is z = (.26 - .2771285476) / .018287644 = -.9366186037.
\n" ); document.write( "test z-score is less than critical z-score of -2.5758.
\n" ); document.write( "this indicates that the test value of .26 is within the 99% confidence interval limits of the sample mean of p.\r
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\n" ); document.write( "\n" ); document.write( "this indicates that the percentage of yellow peas equal to 26% under the same circumstances is reasonable to assume.\r
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\n" ); document.write( "\n" ); document.write( "the test p-value was .1745 which was higher than the critical p-value of .005 on the low end of the confidence interval (.01 / 2 = .005 on the low end of the confidence interval and .005 on the high end of the confidence interval)>\r
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\n" ); document.write( "\n" ); document.write( "Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. \r
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\n" ); document.write( "\n" ); document.write( "null hypothesis is that p = .26 is possible under the same circumstance.
\n" ); document.write( "alternate hypothesis is that p = .26 isn't.
\n" ); document.write( "test p-value = .1745
\n" ); document.write( "this is greater than critical p-value of .005 on the low end of the confidence interval.
\n" ); document.write( "conclusion is that p-value of .26 is entirely reasonable under the same conditions as it is well within the confidence interval.\r
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\n" ); document.write( "\n" ); document.write( "to find the confidence interval limits, do the following.\r
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\n" ); document.write( "\n" ); document.write( "on the low end of the confidence interval, you get -2.5758 = (x - .2771285476) / .018287644.
\n" ); document.write( "solve for x to get x = -2.5758 * .018187644 + .2771285476 = .2300232342.\r
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\n" ); document.write( "\n" ); document.write( "on the high end of the confidence interval, you get 2.5758 = (x - .2771285476) / .018287644.
\n" ); document.write( "solve for x to get x = 2.5758 * .018187644 + .2771285476 = .324233861.\r
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\n" ); document.write( "\n" ); document.write( "your 99% confidence interval is from .2300 to .3242 rounded to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( ".26 is well within those confidence interval limits.
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