document.write( "Question 1205455: Use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beam's width and the square of its depth and inversely proportional to its length.
\n" ); document.write( "A beam 3 cm wide and 5 cm deep can support a load of 630 kg. What load can it support when turned on its side?
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Algebra.Com's Answer #842268 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The given information gives us the following equation:

\n" ); document.write( "\"load=%28%28k%29%28width%29%28depth%5E2%29%29%2Flength\"

\n" ); document.write( "where k is a constant of proportionality.

\n" ); document.write( "We are given the load that can be supported for a given width and depth. But we are not given the length, so we can't determine the constant of proportionality.

\n" ); document.write( "But to solve the problem we don't have to know the value of k. k is some constant, and in this problem the length is a constant. So the difference in the load that can be supported is due to putting the bean on its side -- i.e., switching the width and depth.

\n" ); document.write( "For the load of 630kg, \"%28width%29%28depth%5E2%29=%283%29%285%5E2%29=75\".

\n" ); document.write( "When the beam is turned on its side, \"%28width%29%28depth%5E2%29=%285%29%283%5E2%29=45\".

\n" ); document.write( "So the load that can be supported when the beam is turned on its side is 45/75 = 3/5 of the load it can support in the given configuration.

\n" ); document.write( "630*(3/5)=378

\n" ); document.write( "ANSWER: 378kg

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