document.write( "Question 1205455: Use the fact that the load a beam with a rectangular cross section can support is jointly proportional to the beam's width and the square of its depth and inversely proportional to its length.
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document.write( "A beam 3 cm wide and 5 cm deep can support a load of 630 kg. What load can it support when turned on its side? \n" );
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Algebra.Com's Answer #842268 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The given information gives us the following equation: \n" ); document.write( " \n" ); document.write( "where k is a constant of proportionality. \n" ); document.write( "We are given the load that can be supported for a given width and depth. But we are not given the length, so we can't determine the constant of proportionality. \n" ); document.write( "But to solve the problem we don't have to know the value of k. k is some constant, and in this problem the length is a constant. So the difference in the load that can be supported is due to putting the bean on its side -- i.e., switching the width and depth. \n" ); document.write( "For the load of 630kg, \n" ); document.write( "When the beam is turned on its side, \n" ); document.write( "So the load that can be supported when the beam is turned on its side is 45/75 = 3/5 of the load it can support in the given configuration. \n" ); document.write( "630*(3/5)=378 \n" ); document.write( "ANSWER: 378kg \n" ); document.write( " \n" ); document.write( " |