document.write( "Question 1205441: How do you solve: log5(3x-2)^4=8
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #842247 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "If the 5 refers to base 5, then,
\n" ); document.write( "\"log%285%2C%28%283x-2%29%5E4%29%29+=+8\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4%2Alog%285%2C%283x-2%29%29+=+8\" Pull down the exponent using the rule log(A^B) = B*log(A)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%285%2C%283x-2%29%29+=+8%2F4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%285%2C%283x-2%29%29+=+2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-2+=+5%5E2\" Convert to exponential form.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x-2+=+25\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x+=+25%2B2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x+=+27\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+27%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+9\"
\n" ); document.write( "
\n" ); document.write( "
\n" );