document.write( "Question 1205435: A box contains 15 identical reams of paper. The total mass of the box with 1/5 of all the reams of papers is 33.6 kg lighter than the box with al the reams of paper. The mass of the empty box is 2/7 of a ream of paper. What is the mass of the empty box? \n" ); document.write( "
Algebra.Com's Answer #842226 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "p = mass of one ream of paper in kg \n" ); document.write( "(2/7)p = mass of the empty box in kg\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = mass of empty box and 3 reams of paper \n" ); document.write( "A = (2/7)p + 3p \n" ); document.write( "A = (2/7 + 3)p \n" ); document.write( "A = (2/7 + 21/7)p \n" ); document.write( "A = (23/7)p \n" ); document.write( "Note that 3 reams is 1/5 of the total 15 reams.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B = mass of empty box and 15 reams of paper \n" ); document.write( "B = (2/7)p + 15p \n" ); document.write( "B = (2/7 + 15)p \n" ); document.write( "B = (2/7 + 105/7)p \n" ); document.write( "B = (107/7)p \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mass A is 33.6 kg lighter compared to mass B. \n" ); document.write( "A = B - 33.6 \n" ); document.write( "(23/7)p = (107/7)p - 33.6 \n" ); document.write( "7*(23/7)p = 7*( (107/7)p - 33.6 ) \n" ); document.write( "23p = 107p - 235.2 \n" ); document.write( "23p-107p = -235.2 \n" ); document.write( "-84p = -235.2 \n" ); document.write( "p = -235.2/(-84) \n" ); document.write( "p = 2.8 \n" ); document.write( "Each ream of paper has a mass of 2.8 kg.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2/7)*p = (2/7)*2.8 = 0.8 kg is the mass of the empty box.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notes: \n" ); document.write( "2.8 = 14/5 \n" ); document.write( "0.8 = 4/5 \n" ); document.write( " \n" ); document.write( " |