document.write( "Question 1205419: The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 77 minutes and a standard deviation of 14 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible.\r
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\n" ); document.write( "\n" ); document.write( "c. The park service is considering offering a discount for the 4% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount?
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\n" ); document.write( "\n" ); document.write( "d. Find the Inter Quartile Range (IQR) for time spent at the hot springs.
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Algebra.Com's Answer #842207 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I'll focus on the 1st problem only. I'll mark it in blue.
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\n" ); document.write( "The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 77 minutes and a standard deviation of 14 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible.\r
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\n" ); document.write( "\n" ); document.write( "c. The park service is considering offering a discount for the 4% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount?
\n" ); document.write( "minutes.
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\n" ); document.write( "\n" ); document.write( "As mentioned by tutor Theo, you can use the online calculator at the link he posted.
\n" ); document.write( "The calculator is very user friendly and provides a nice diagram. \r
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\n" ); document.write( "\n" ); document.write( "For exam purposes, your teacher may not let you use that calculator (or similar online calculators). It's possible your teacher may only allow something like a TI83 or TI84. \r
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\n" ); document.write( "\n" ); document.write( "If so, then check out this resource
\n" ); document.write( "https://www.statology.org/inverse-normal-distribution/
\n" ); document.write( "It explains how to reach the invNorm function.\r
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\n" ); document.write( "\n" ); document.write( "In this case you'll type in:
\n" ); document.write( "invNorm(0.04)
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\n" ); document.write( "The result of that command is approximately -1.750686\r
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\n" ); document.write( "\n" ); document.write( "It will mean P(z < -1.750686) = 0.04 approximately.
\n" ); document.write( "The area under the curve to the left of z = -1.750686 is roughly 0.04
\n" ); document.write( "4% of the distribution is below the approximate cut off point of z = -1.750686\r
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\n" ); document.write( "\n" ); document.write( "We'll use this to find the corresponding raw score x.
\n" ); document.write( "z = (x - mu)/sigma
\n" ); document.write( "z*sigma = x - mu
\n" ); document.write( "x = z*sigma + mu
\n" ); document.write( "x = -1.750686*14 + 77
\n" ); document.write( "x = 52.490396
\n" ); document.write( "x = 52.4904 when rounding to 4 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "The longest amount of time that can be spent is approximately 52.4904 minutes, and you will be in the \"lowest 4%\" category to get the discount.
\n" ); document.write( "Any time higher than this will land you in the upper 96% of the distribution.\r
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\n" ); document.write( "\n" ); document.write( "If you aren't allowed a calculator, then use of a Z table is the only other option.\r
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\n" ); document.write( "\n" ); document.write( "Here's one such table
\n" ); document.write( "https://www.ztable.net/
\n" ); document.write( "Tables like this should be found at the back of your stats textbook.
\n" ); document.write( "Your teacher should likely hand them out as a reference sheet during exams.\r
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\n" ); document.write( "\n" ); document.write( "The idea is to find the value of k such that P(Z < k) = 0.04
\n" ); document.write( "Unfortunately the exact value 0.04 is NOT inside the table.
\n" ); document.write( "The closest we can get is 0.04006
\n" ); document.write( "This value can be found at the row starting with \"-1.7\" and in the column with \"0.05\" at the top.
\n" ); document.write( "This means P(Z < -1.75) = 0.04006 approximately, which is roughly the same as P(Z < -1.75) = 0.04\r
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\n" ); document.write( "\n" ); document.write( "Once you determine the proper z value, convert it to the raw score x as shown here:
\n" ); document.write( "z = (x - mu)/sigma
\n" ); document.write( "x = z*sigma + mu
\n" ); document.write( "x = -1.75*14 + 77
\n" ); document.write( "x = 52.5
\n" ); document.write( "We get a slightly different answer because we're using a less accurate z value.
\n" ); document.write( "Luckily 52.5 is close to 52.4904
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