document.write( "Question 1205417: A roll of tape is on a spool with diameter 3.6 cm. The diameter of the spool plus the diameter of the tape is 5.4 cm. The tape is 25.4 m long. The number of layers on the tape is closest to \r
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Algebra.Com's Answer #842196 by ikleyn(52858)\"\" \"About 
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\n" ); document.write( "A roll of tape is on a spool with diameter 3.6 cm. The diameter of the spool plus the diameter
\n" ); document.write( "of the tape is 5.4 cm. The tape is 25.4 m long. The number of layers on the tape is closest to
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\n" ); document.write( "e) 1773
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document.write( "The minimum diameter (the diameter of the first layer) is d = 3.6 cm; \r\n" );
document.write( "the circumference (the length) of the first layer is  \"pi%2Ad\" = 3.14159*3.6 = 11.309724 cm.\r\n" );
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document.write( "The maximum diameter (the diameter of the last layer) is D = 5.4 cm; \r\n" );
document.write( "the circumference (the length) of the last layer is  \"pi%2AD\" = 3.14159*5.4 = 16.964586 cm.\r\n" );
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document.write( "The lengths of consecutive layers make an arithmetic progression with the common  difference  \"2%2Api%2Adelta\",\r\n" );
document.write( "where  \"delta\"  is the thickness of the tape. Therefore, the number of layers n can be found from \r\n" );
document.write( "the formula of the sum of an arithmetic progression\r\n" );
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document.write( "    2540 = \"%28%28first_term%2Blast_term%29%2F2%29%2An\" = \"%28%2811.309724%2B16.964586%29%2F2%29%2An\" = 14.137155*n,\r\n" );
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document.write( "    n = \"2540%2F14.137155%29\" = 179.67  (approximately).\r\n" );
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document.write( "ANSWER.  The number of layers on the tape (approximately 180), is closest to option b).\r\n" );
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