document.write( "Question 1205398: A train normally travels between two stations at v km/h. If its average speed is increased in the ratio m:n, will it take more or less time?
\n" ); document.write( "In what ratio is the time changed?
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Algebra.Com's Answer #842172 by Theo(13342)\"\" \"About 
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if the speed is increased, then it will take less time.
\n" ); document.write( "example:
\n" ); document.write( "v is the original speed.
\n" ); document.write( "it is increased by the ratio m:n
\n" ); document.write( "if it is increased, then m must be greater than v.\r
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\n" ); document.write( "\n" ); document.write( "increase in a ratio means to multiply the original value by by a fraction where the numerator is greater than the denominator.\r
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\n" ); document.write( "\n" ); document.write( "v * m/n is greater than v.\r
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\n" ); document.write( "\n" ); document.write( "if the speed is increased, the time to get to the destination will be less.\r
\n" ); document.write( "\n" ); document.write( "note that these problems use the general formula of r * t = d.
\n" ); document.write( "r is the speed of the vehicle.
\n" ); document.write( "t is the time it takes the vehicle to get to the destination.
\n" ); document.write( "d is the distance to get to the destination.\r
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\n" ); document.write( "\n" ); document.write( "example:\r
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\n" ); document.write( "\n" ); document.write( "r*t=d becomes 5*5=25 when r = 5 and t = 5.
\n" ); document.write( "the rate of the vehicle is 5 kilometers per hour.
\n" ); document.write( "the time it takes to the destination is 5 hours.
\n" ); document.write( "the distance if 5 kilometers per hour * 5 hours = 25 kilometers.\r
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\n" ); document.write( "\n" ); document.write( "if you multiply r by 5/2, then r = 5 * 5/2 = 25/2 = 12.5
\n" ); document.write( "the new speed of the vehicle becomes 12.5 kilometers per hour.\r
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\n" ); document.write( "\n" ); document.write( "rt=d becomes 12.5 * t = 25
\n" ); document.write( "solve for t to get t = 25/12.5 = 2\r
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\n" ); document.write( "\n" ); document.write( "speed was increased, therefore time was decreased.\r
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\n" ); document.write( "\n" ); document.write( "in what ratio was the time changed?\r
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\n" ); document.write( "\n" ); document.write( "see below.\r
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\n" ); document.write( "\n" ); document.write( "the formula is R * T = D
\n" ); document.write( "when you increase the rate by m/n, then the formula becomes R * n/m * T = D
\n" ); document.write( "if you divide both sides of the formula by R, you get m/n * T = D/R
\n" ); document.write( "if you multiply both sides of the equation by n/m, you get T = D/R * n/m
\n" ); document.write( "so your answer for in what ratio is the time changed should be n/m.
\n" ); document.write( "in my example, the original value of t was 5.
\n" ); document.write( "after multiplying the rate by 5/2, t was then 2.
\n" ); document.write( "so t must have been multiplied by 2/5 because 5 * 2/5 = 2
\n" ); document.write( "if 5/2 was m/n, then 2/5 must be n/m.\r
\n" ); document.write( "\n" ); document.write( "let me know if if your have any questions.\r
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\n" ); document.write( "\n" ); document.write( "theo\r
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