document.write( "Question 1205379: Cheyenne tells a joke to 5 people and those 5 people tell the joke to 5 more people, and so on. Which expression shows the number of people that will hear the joke after the sixth round?\r
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Algebra.Com's Answer #842130 by MathLover1(20850)\"\" \"About 
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On the first round \"5=5%5E1+\"people hear the joke
\n" ); document.write( "On the second round, those \"5+\"people each tell \"5+\"more people, so \"5%2A5+=+25+=5%5E2\" people hear the joke.
\n" ); document.write( "On the third round, those \"25\" people each tell \"5\" more people, so \"25%2A5+=+125=5%5E3\" people hear the joke.
\n" ); document.write( "On the fourth round, those \"125\" people each tell \"5\"more people, so \"125%2A5+=+625=5%5E4+\"people hear the joke.
\n" ); document.write( "On the fifth round, those \"625\" people each tell\"+5+\"more people, so\"+625%2A5+=+3125=5%5E5+\"people hear the joke.
\n" ); document.write( "On the sixth round, those \"3125\" people each tell \"5\" more people, so \"3125%2A5+=+15625=5%5E6\" people hear the joke.\r
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\n" ); document.write( "\n" ); document.write( "expression \"5%5E6\" shows the number of people that will hear the joke after the sixth round\r
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\n" ); document.write( "\n" ); document.write( "general formula:\r
\n" ); document.write( "\n" ); document.write( "\"y=5%5Ex\" where \"x\" is the number of rounds and \"y+\"the number of people hear the joke\r
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