document.write( "Question 1205373: The perimeter of a rectangle is 48cm. The length of a rectangle is 3cm longer than twice its width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #842119 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Answer: 17 cm by 7 cm\r
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\n" ); document.write( "\n" ); document.write( "Work Shown\r
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\n" ); document.write( "\n" ); document.write( "w = width
\n" ); document.write( "2w+3 = length\r
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\n" ); document.write( "\n" ); document.write( "2*(length + width) = perimeter of rectangle
\n" ); document.write( "2*(2w+3 + w) = 48
\n" ); document.write( "2*(3w+3) = 48
\n" ); document.write( "6w+6 = 48
\n" ); document.write( "6w = 48-6
\n" ); document.write( "6w = 42
\n" ); document.write( "w = 42/6
\n" ); document.write( "w = 7 cm is the width
\n" ); document.write( "2w+3 = 2*7+3 = 17 cm is the length\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "perimeter = 2*(length+width) = 2*(17+7) = 2*24 = 48 cm
\n" ); document.write( "We have confirmed the answers.
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