document.write( "Question 1205308: A factory manufactures light bulbs for distribution under 2 different brands. Brand A bulbs have an
\n" ); document.write( "average life of 1800 hours with a standard deviation of 240 hours; Those of mark B have an average life
\n" ); document.write( "of 1450 hours with a standard deviation of 150 hours. A sample of 250 light bulbs is taken from each
\n" ); document.write( "brand. Describe completely this situation, define all the data, and explain the method and all steps of
\n" ); document.write( "computation. How likely is the average lifespan of Brand A bulbs to be at least 400 hours longer than
\n" ); document.write( "that of Brand B bulbs?
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Algebra.Com's Answer #842073 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this is my best shot at what i think is the way to analyze this.
\n" ); document.write( "i'm using a two sample z-test.
\n" ); document.write( "referenceto that can be found at \r
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\n" ); document.write( "\n" ); document.write( "brand A has a mean of 1800 with a standard deviation of 240.
\n" ); document.write( "brand B has a mean of 2450 with a standard deviation of 150.
\n" ); document.write( "a sample of size 250 is taken from the population of both brands.\r
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\n" ); document.write( "\n" ); document.write( "the mean of brand A is compared to the mean of brand B using a two sample z-test.
\n" ); document.write( "z-score formula is z = (x-m)/s
\n" ); document.write( "z is he z-score.
\n" ); document.write( "x is the mean of brand A.
\n" ); document.write( "m is the mean of brand B.
\n" ); document.write( "s is the standard error.\r
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\n" ); document.write( "\n" ); document.write( "s = sqrt(d1^2/n1 + d2^2/n2)
\n" ); document.write( "d1 is the standard deviation of brand A.
\n" ); document.write( "d2 is the standard deviation of brand B.
\n" ); document.write( "n1 and n2 are the sample size of brand A and brand B.
\n" ); document.write( "this is the same at 250.
\n" ); document.write( "formula becomes s = sqrt(240^2/250 + 150^2/250) = 17.89972.\r
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\n" ); document.write( "\n" ); document.write( "z-score formula becomes z = (1800 - 1450) / 17.89972 = 19.55613.
\n" ); document.write( "this is a very high z-score, indicating that the mean of brand A is clearly greater than the mean of brand B and that the probability of getting a difference greater than 350 is effectively 0.\r
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\n" ); document.write( "\n" ); document.write( "based on that, then the probability of getting a mean for brand A that is more than 400 hours greater than the mean for brand B is even less probable, meaning that it is also effectively 0.\r
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\n" ); document.write( "\n" ); document.write( "here are the results of the two sample t-test using the calculator at https://www.statskingdom.com/120MeanNormal2.html\r
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