document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1205336>Question 1205336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> problem 1:\r<BR>\n" );
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document.write( "A cyclist, riding steadily from his hometown, reached his destination in 4.5 h. He would have taken 45 min less time if he had ridden his bicycle at a speed faster by 3 km/h. Find the distance from his hometown to his destination. \r<BR>\n" );
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document.write( "problem 2:\r<BR>\n" );
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document.write( "At 9:30 am, car A started its journey and travelled at 65 km/h. At 11:00 am, car B started its journey from the same place and travelled on the same road as car A. If car B , travelling at a constant speed, took five hours to catch up with car A, find the speed of car B.<BR>\n" );
document.write( "SHOW LESS </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #842072 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20054)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=842072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 9:30 am, car A started its journey and travelled at 65 km/h. At 11:00 am, car<BR>\n" );
document.write( "B started its journey from the same place and travelled on the same road as car<BR>\n" );
document.write( "A. If car B , travelling at a constant speed, took five hours to catch up with<BR>\n" );
document.write( "car A, find the speed of car B.<BR>\n" );
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document.write( "Let r = the speed of car B\r\n" );
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document.write( "At 11 AM, car A had already been traveling 1.5 hours at 65 km/h, and therefore\r\n" );
document.write( "was (1.5)(65) = 97.5 kilometers down the road.\r\n" );
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document.write( "The catch-up rate is the difference of their speeds, r-65 km/h\r\n" );
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document.write( "To reduce the 97.5 km to 0 in a 5 hour time period, we use \r\n" );
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document.write( "(rate)(time)=distance\r\n" );
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document.write( "(r-65)(5) = 97.5\r\n" );
document.write( " 5r - 325 = 97.5\r\n" );
document.write( "       5r = 422.5\r\n" );
document.write( "        r = 84.5 km/h\r\n" );
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document.write( "Edwin</PRE>\r<BR>\n" );
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