document.write( "Question 1205334: a bank loaned out $15000, part of it at 8% per year, the rest at 18% per year. if the interest received in one year totaled $2000, how much was loaned at 8%? \n" ); document.write( "

Algebra.Com's Answer #842067 by ikleyn(52908) $\"\"$ $\"About$

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\n" ); document.write( "15000 total part of it at 0.08 per year, the rest at 0.18 per year.
\n" ); document.write( "if received in one year totaled 2000, how much was loaned at 0.08?
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document.write( "x at 0.08; the rest, (15000--x), at 0.18.\r\n" );
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document.write( "Write equation for the annual interest\r\n" );
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document.write( "    0.08x + 0.18*(15000-x) = 2000.\r\n" );
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document.write( "Simplify and solve for x\r\n" );
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document.write( "    0.08x + 0.18*15000 - 0.18x = 2000\r\n" );
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document.write( "    0.08x - 0.18x = 2000 - 0.18*15000\r\n" );
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document.write( "      -0.1x       =   -700\r\n" );
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document.write( "          x       = -700/(-0.1) = 70000.\r\n" );
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document.write( "ANSWER.  7000 at 0.08.\r\n" );
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