document.write( "Question 1205334: a bank loaned out $15000, part of it at 8% per year, the rest at 18% per year. if the interest received in one year totaled $2000, how much was loaned at 8%? \n" ); document.write( "
Algebra.Com's Answer #842066 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Total amount loaned = $\"15000\"\r
\n" ); document.write( "\n" ); document.write( "\"x+\"= total amount loaned at \"8\"%=\"0.08\"
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\n" ); document.write( "\"y\" = total amount loaned at\"18\"%=\"+0.18+\"
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\n" ); document.write( "so,
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\n" ); document.write( "\"x+%2B+y+=+15000\"....solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=15000-y\".......eq.1\r
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\n" ); document.write( "\n" ); document.write( "if received in one year totaled \"2000\" in one year\r
\n" ); document.write( "\n" ); document.write( "\"0.08x+%2B+0.18y+=+2000\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"0.08%2815000-y%29+%2B+0.18y+=+2000\"\r
\n" ); document.write( "\n" ); document.write( "\"1200+-+0.08y%2B+0.18y+=+2000\"\r
\n" ); document.write( "\n" ); document.write( " \"0.10y+=+2000-1200+\"\r
\n" ); document.write( "\n" ); document.write( "\"+0.10y+=+800\"\r
\n" ); document.write( "\n" ); document.write( "\"y=800%2F0.10\"\r
\n" ); document.write( "\n" ); document.write( "\"y=8000\"\r
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\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"x=15000-y\".......eq.1, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=15000-8000\"\r
\n" ); document.write( "\n" ); document.write( "\"x=7000\"\r
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\n" ); document.write( "\n" ); document.write( " answer: $\"7000+\"was loaned at \"8\"%
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