document.write( "Question 1205331: Find the sum of the following series:\r
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Algebra.Com's Answer #842057 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Each term is of the form \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rationalize the denominator, by multiplying top and bottom by \n" ); document.write( "Therefore, \n" ); document.write( "I'll leave the scratch work for the student to do.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If k = 1, then, \n" ); document.write( "If k = 2, then, \n" ); document.write( "If k = 3, then, \n" ); document.write( "Adding those terms gets us \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The inner terms \n" ); document.write( "This will extend to the summation of terms k = 1 through k = 35 \n" ); document.write( "The inner terms \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For more info and examples, search out \"telescoping series\". \n" ); document.write( "The name is due to the fact the long series collapses to a very small expression since the inner terms cancel out. \n" ); document.write( "https://mathworld.wolfram.com/TelescopingSum.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: 5 \n" ); document.write( " \n" ); document.write( " |