document.write( "Question 1205331: Find the sum of the following series:\r
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Algebra.Com's Answer #842057 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Each term is of the form \"1%2F%28sqrt%28k%29%2Bsqrt%28k%2B1%29%29\" where k ranges from k = 1 to k = 35.\r
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\n" ); document.write( "\n" ); document.write( "Rationalize the denominator, by multiplying top and bottom by \"sqrt%28k%29-sqrt%28k%2B1%29\", and you should get \"sqrt%28k%2B1%29-sqrt%28k%29\" after the simplification is done.
\n" ); document.write( "Therefore, \"1%2F%28sqrt%28k%29%2Bsqrt%28k%2B1%29%29+=+sqrt%28k%2B1%29-sqrt%28k%29\"
\n" ); document.write( "I'll leave the scratch work for the student to do.\r
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\n" ); document.write( "\n" ); document.write( "If k = 1, then, \"sqrt%28k%2B1%29-sqrt%28k%29+=+sqrt%281%2B1%29-sqrt%281%29=+sqrt%282%29-sqrt%281%29\"
\n" ); document.write( "If k = 2, then, \"sqrt%28k%2B1%29-sqrt%28k%29+=+sqrt%282%2B1%29-sqrt%282%29=+sqrt%283%29-sqrt%282%29\"
\n" ); document.write( "If k = 3, then, \"sqrt%28k%2B1%29-sqrt%28k%29+=+sqrt%283%2B1%29-sqrt%283%29=+sqrt%284%29-sqrt%283%29\"
\n" ); document.write( "Adding those terms gets us
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\n" ); document.write( "\n" ); document.write( "The inner terms \"sqrt%282%29\" and \"sqrt%283%29\" cancel out.
\n" ); document.write( "This will extend to the summation of terms k = 1 through k = 35
\n" ); document.write( "The inner terms \"sqrt%282%29\", \"sqrt%283%29\", ... , \"sqrt%2834%29\", \"sqrt%2835%29\" cancel leaving behind \"sqrt%2836%29-sqrt%281%29+=+6-1+=+5\"\r
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\n" ); document.write( "\n" ); document.write( "For more info and examples, search out \"telescoping series\".
\n" ); document.write( "The name is due to the fact the long series collapses to a very small expression since the inner terms cancel out.
\n" ); document.write( "https://mathworld.wolfram.com/TelescopingSum.html\r
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\n" ); document.write( "\n" ); document.write( "Answer: 5
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