document.write( "Question 115727: Please solve for all values of x
\n" ); document.write( "x/(x+3)= 5/(x+7)\r
\n" ); document.write( "\n" ); document.write( "question from practice regents
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Algebra.Com's Answer #84202 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x/(x+3)= 5/(x+7)\r
\n" ); document.write( "\n" ); document.write( "x(x+7) = 5(x+3)
\n" ); document.write( "x^2+7x = 5x+15
\n" ); document.write( "x^2+2x-15 = 0
\n" ); document.write( "(x+5)(x-3) = 0
\n" ); document.write( "x = -5 or x = 3
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\n" ); document.write( "But x cannot be 3 in the original equation.
\n" ); document.write( "Therefore x=-5 is the only solution.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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