document.write( "Question 1205292: a shoe manufacturing company is producing 50,000 pairs of shoes daily. from a sample of 500 pairs, 2% are found to be of substandard quality. at 95% level of confidence, estimate the number of pairs of shoes that are reasonably expected to be spolied in the daily production. \n" ); document.write( "
Algebra.Com's Answer #842010 by Theo(13342)![]() ![]() You can put this solution on YOUR website! production is 50,000 pairs of shoes daily. \n" ); document.write( "sample size is 500. \n" ); document.write( "2% of the 500 were found to be of substandard quality. \n" ); document.write( ".02 * 500 = 10. \n" ); document.write( "10 out of the 500 were found to be defective. \n" ); document.write( "the mean is 10. \n" ); document.write( "the standard deviation is sqrt(n * p * q) = sqrt(500 * .02 * .98) = 3.130495.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "critical z-score at 95% two tail confidence interval is equal to plus or minus 1.96.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the low end of the confidence interval, the formula becomes -1.96 = (x - 10) / 3.120495. \n" ); document.write( "solve for x to get x = 3.86423.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the high end of the confidence interval, the formula becomes 1.96 * (x - 10) / 3.120495. \n" ); document.write( "solve for x to get x = 16.13577.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your 95% confidence interval is from 3.86423 to 16.13577.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's what it looks like on a normal distribution graph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |