document.write( "Question 17475: I need help evaluating this expression:\r
\n" ); document.write( "\n" ); document.write( "Log base 10 multiplied to (.01) raised to the 3rd power\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "Michael V
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Algebra.Com's Answer #8420 by bam878s(77)\"\" \"About 
You can put this solution on YOUR website!
throughout assume log = log base 10
\n" ); document.write( "we know log 1 = 0
\n" ); document.write( "why?
\n" ); document.write( "because \"10%5E0\" = 1\r
\n" ); document.write( "\n" ); document.write( "From properties of log we know
\n" ); document.write( "log \"x%5En\" = n log x
\n" ); document.write( "so log \".01%5E3\" = 3 log .01\r
\n" ); document.write( "\n" ); document.write( "now we just need to find log .01
\n" ); document.write( "note .01 = \"1%2F100\" = \"1%2F%2810%5E2%29\" = \"10%5E-2\"
\n" ); document.write( "so \"10%5E-2\" = .01 means that log .01 = -2\r
\n" ); document.write( "\n" ); document.write( "so now 3 log .01 = 3 * (-2) = -6\r
\n" ); document.write( "\n" ); document.write( "Hope this helps
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