document.write( "Question 1205268: What number is in between -2 and -0.75\r
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Algebra.Com's Answer #841950 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are infinitely many numbers between -2 and -0.75, but one number we could pick on is the midpoint.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add up the values and then divide in half\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add: -2+(-0.75) = -2-0.75 = -2.75 \n" ); document.write( "Divide in half: -2.75/2 = -1.375 \n" ); document.write( "The value -1.375 is between -2 and -0.75 \n" ); document.write( "This is known as the arithmetic mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or we could apply the geometric mean \n" ); document.write( "Multiply the values and then apply the square root.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply: -2*(-0.75) = 1.5 \n" ); document.write( "sqrt(1.5) = 1.2247 approximately \n" ); document.write( "Make the result negative so it's in between the two negative values \n" ); document.write( "-1.2247 approximately is between -2 and -0.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Edit: @ikleyn, fair enough, the geometric mean approach seemed a bit flimsy. However, we could treat it like finding the geometric mean of 2 and 0.75 and then make the result negative. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another thing we could do is find the distance between the given values \n" ); document.write( "distance = |a-b| = |-2-(-0.75)| = |-2+0.75| = |-1.25| = 1.25 \n" ); document.write( "Then cut this distance into N pieces, let's say N = 10 \n" ); document.write( "1.25/N = 1.25/10 = 0.125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let k be some integer on the interval 0 < k < N \n" ); document.write( "In this case 0 < k < 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then let's add some multiple of 0.125 to the left endpoint -2, to land somewhere between -2 and -0.75 \n" ); document.write( "We're evaluating -2+0.125k for k = 1 through k = 9 \n" ); document.write( "If k = 1, then -2 + 0.125k = -2 + 0.125*1 = -1.875 \n" ); document.write( "If k = 2, then -2 + 0.125k = -2 + 0.125*2 = -1.75 \n" ); document.write( "If k = 3, then -2 + 0.125k = -2 + 0.125*3 = -1.625 \n" ); document.write( "If k = 4, then -2 + 0.125k = -2 + 0.125*4 = -1.5 \n" ); document.write( "If k = 5, then -2 + 0.125k = -2 + 0.125*5 = -1.375 \n" ); document.write( "If k = 6, then -2 + 0.125k = -2 + 0.125*6 = -1.25 \n" ); document.write( "If k = 7, then -2 + 0.125k = -2 + 0.125*7 = -1.125 \n" ); document.write( "If k = 8, then -2 + 0.125k = -2 + 0.125*8 = -1 \n" ); document.write( "If k = 9, then -2 + 0.125k = -2 + 0.125*9 = -0.875 \n" ); document.write( "Each of the results {-1.875, -1.75, -1.625, -1.5, -1.375, -1.25, -1.125, -1, -0.875} are between -2 and -0.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notes: If k = 0, then -2+0.125k = -2 is the left endpoint, while k = 10 means -2+0.125k = -0.75 is the right endpoint.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There's nothing special about N = 10. We could have easily made N = 20 or whatever positive whole number you want.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And yet another approach is to select the number -1 since it's between -2 and -0.75, and then tack on some random string of decimal digits. \n" ); document.write( "Eg: -1.2345 or -1.6789 \n" ); document.write( " \n" ); document.write( " |