document.write( "Question 115710This question is from textbook
\n" ); document.write( ": x^2-x-13=0 \n" ); document.write( "
Algebra.Com's Answer #84195 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2-x-13=0\" ( notice \"a=1\", \"b=-1\", and \"c=-13\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28--1+%2B-+sqrt%28+%28-1%29%5E2-4%2A1%2A-13+%29%29%2F%282%2A1%29\" Plug in a=1, b=-1, and c=-13\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%2A1%2A-13+%29%29%2F%282%2A1%29\" Negate -1 to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-4%2A1%2A-13+%29%29%2F%282%2A1%29\" Square -1 to get 1 (note: remember when you square -1, you must square the negative as well. This is because \"%28-1%29%5E2=-1%2A-1=1\".)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1%2B52+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-13%2A1\" to get \"52\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+53+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%2853%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%2853%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B+sqrt%2853%29%29%2F2\" or \"x+=+%281+-+sqrt%2853%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2B1%2F2%2Bsqrt%2853%29%2F2\" or \"x=%2B1%2F2-sqrt%2853%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x=1+%2F+2%2Bsqrt%2853%29%2F2\" or \"x=1+%2F+2-sqrt%2853%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=4.14005494464026\" or \"x=-3.14005494464026\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=4.14005494464026\" or \"x=-3.14005494464026\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2-x-13\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=4.14005494464026\" and \"x=-3.14005494464026\".So this verifies our answer\r
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