document.write( "Question 1205238: How many different arrangements can be formed by taking 4 letters from the word
\n" ); document.write( "STATISTICS? Assume that the letters are taken without replacement.
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Algebra.Com's Answer #841909 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are 5 different letters: 3 each of S and T, 2 of I, and 1 each of A and C.

\n" ); document.write( "To choose 4 letters, we have the following different cases to consider:
\n" ); document.write( "(1) 3 of one letter and 1 of a different letter
\n" ); document.write( "(2) 2 each of two different letters
\n" ); document.write( "(3) 2 of one letter and 1 each of two other letters
\n" ); document.write( "(4) 4 different letters

\n" ); document.write( "(1) 3 and 1. We need to...
\n" ); document.write( "choose one of the two letters that occurs 3 times: C(2,1)=2
\n" ); document.write( "choose one of the other 4 letters: C(4,1)=4
\n" ); document.write( "arrange the 4 letters in any of \"4%21%2F%28%283%21%29%281%21%29%29=4\" ways

\n" ); document.write( "Number of arrangements: (2)(4)(4) = 32

\n" ); document.write( "(2) 2 and 2. We need to...
\n" ); document.write( "choose two of the three letters that occurs 2 or more times: C(3,2)=3
\n" ); document.write( "arrange the 4 letters in any of \"4%21%2F%28%282%21%29%282%21%29%29=6\" ways

\n" ); document.write( "Number of arrangements: (3)(6) = 18

\n" ); document.write( "(3) 2, 1, and 1. We need to...
\n" ); document.write( "choose one of the three letters that occurs 2 or more times: C(3,1)=3
\n" ); document.write( "choose two of the other 4 letters: C(4,2)=6
\n" ); document.write( "arrange the 4 letters in any of \"4%21%2F%28%282%21%29%281%21%29%281%21%29%29=12\" ways

\n" ); document.write( "Number of arrangements: (3)(6)(12) = 216

\n" ); document.write( "(4) 1, 1, 1, and 1. We need to...
\n" ); document.write( "choose any 4 of the 5 letters: C(5,4)=1
\n" ); document.write( "arrange the 4 letters in any of 4! = 24 ways

\n" ); document.write( "Number of arrangements: (5)(24) = 120

\n" ); document.write( "Total number of arrangements: 32+18+216+120 = 386

\n" ); document.write( "ANSWER: 386

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