document.write( "Question 1205216: If lim f(x)=a where x-->0^+
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document.write( ", lim f(x)=b where x-->0^-
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document.write( ", then lim f(x²) × f(x³-x) =..... where x-->0^- \n" );
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Algebra.Com's Answer #841885 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " DUPLICATE\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "If x-->0^+ (in other words, if x approaches 0 from the right), then x^2 approaches 0 from the right, too.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "If x-->0^- (in other words, if x approaches 0 from the left), then (x^3-x) approaches 0 from the left (sic !).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "THEREFORE, the ANSWER to the problem's question is a*b.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved, with complete explanation.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |