document.write( "Question 1205208: graph y= 1/2x-4 \n" ); document.write( "
Algebra.Com's Answer #841871 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I think I'll just change to other one I posted for this student.\r\n" );
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document.write( "The other tutor showed one way to graph the line, but I think you may just\r\n" );
document.write( "be starting graphing lines from their equations, and you need this more\r\n" );
document.write( "elementary method:\r\n" );
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document.write( "\"y=expr%281%2F2%29x-4\". That is in slope-intercept form \"y=mx%2Bb\"\r\n" );
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document.write( "Some teachers teach it this way: \"b\" stands for \"BEGIN\" and \"m\" stands \r\n" );
document.write( "for \"MOVE\".  You BEGIN at the y-intercept, and then you MOVE from there, \r\n" );
document.write( "as described below:\r\n" );
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document.write( "the slope is \"m=1%2F2\" and the y-intercept is \"b=-4\".  The \r\n" );
document.write( "y-intercept, b, means that we BEGIN where the line intersects the y-axis\r\n" );
document.write( "at the point (0,b), which in this case is the point (0,-4).\r\n" );
document.write( "[That's where you \"BEGIN\". (Think of \"b\" as if it stood for \"BEGIN\".)\r\n" );
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document.write( "So we mark the y-intercept point (0,-4), like this:\r\n" );
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document.write( "Now we MOVE from the y-intercept (0,-4):\r\n" );
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document.write( "1. The slope is positive so this means from that point we go UPWARD the NUMERATOR of\r\n" );
document.write( "the slope. (When the slope is negative we go DOWN, but in this case we go UP).\r\n" );
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document.write( "The NUMERATOR of the slope, \"1%2F2\" is 1, and positive, so we draw the line\r\n" );
document.write( "segment UPWARD from\r\n" );
document.write( "the y-intercept). So we draw a line segment from the y-intercept (0,-4) up 1\r\n" );
document.write( "unit, from (0,-4) to (0,-3), like this:\r\n" );
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document.write( "2. Now from there, at the point (0,-3), we draw a line TO THE RIGHT (ALWAYS to\r\n" );
document.write( "the RIGHT) the DENOMINATOR of the slope, which is 2 units RIGHT.  It goes from\r\n" );
document.write( "the point (0,-3) to the RIGHT to the point (2,-3), like this:\r\n" );
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document.write( "Finally we draw a line, through the point we BEGAN at (0,-4), and the point we\r\n" );
document.write( "MOVED TO or ended up at, (2,-3), and that is the graph of the line whose\r\n" );
document.write( "equation is \"y=expr%281%2F2%29x-4\".\r\n" );
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document.write( "You should LEARN: \r\n" );
document.write( "1. that a line which has a POSITIVE number for its slope, always\r\n" );
document.write( "leans to the RIGHT, like this one, and a line which has a NEGATIVE number for\r\n" );
document.write( "its slope always leans to the LEFT.  \r\n" );
document.write( "2. that the GREATER the (absolute value) of the slope, the STEEPER the line.\r\n" );
document.write( "3. if the slope is 1 or -1, the line is at an angle of 45o.\r\n" );
document.write( "If the slope is a fraction or number less than 1, it is LESS STEEP than 45o and \r\n" );
document.write( "if the slope is a fraction or number greater than 1, it is STEEPER than 45o.\r\n" );
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document.write( "Edwin
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