document.write( "Question 1205185: Hi
\n" ); document.write( "Ted and Justina took part in a race. Ted won the race 25 minutes after it started. Justina had only run 5/8 of the distance. Justinas average speed was 75 m per minute slower than Ted. What was Ted's average speed in the race
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Algebra.Com's Answer #841827 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "x = Ted's speed
\n" ); document.write( "x-75 = Justina's speed
\n" ); document.write( "Each speed is in meters per minute.\r
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\n" ); document.write( "\n" ); document.write( "For Ted,
\n" ); document.write( "distance = rate*time
\n" ); document.write( "distance = (x meters per min)*(25 min)
\n" ); document.write( "distance = 25x\r
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\n" ); document.write( "\n" ); document.write( "Now find the distance Justina traveled in the same 25 minute time frame.
\n" ); document.write( "distance = rate*time
\n" ); document.write( "distance = (x-75)*(25)
\n" ); document.write( "distance = 25(x-75)
\n" ); document.write( "distance = 25x-1875\r
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\n" ); document.write( "\n" ); document.write( "Ted ran 25x meters which is the full track.
\n" ); document.write( "Justina ran 25x-1875 meters (i.e. 1875 meters less than a full track). Her distance is 5/8 of Ted's distance.\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "Justina's distance = (5/8)*(Ted's distance)
\n" ); document.write( "25x-1875 = (5/8)*(25x)
\n" ); document.write( "8(25x-1875) = 5(25x)
\n" ); document.write( "200x - 15000 = 125x
\n" ); document.write( "200x-125x = 15000
\n" ); document.write( "75x = 15000
\n" ); document.write( "x = 15000/75
\n" ); document.write( "x = 200\r
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\n" ); document.write( "\n" ); document.write( "200 meters per minute might sound like a lot, but it converts to roughly 7.456 mph, which is a typical average running speed.
\n" ); document.write( "Sprinting speeds will likely exceed this, but keep in mind that we're talking about an overall average over the course of 25 minutes.
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