document.write( "Question 1205147: The area of a rectangle is 12cm^2. Find the range of possible values of the width of the rectangle if the diagonal is more than 5cm. \n" ); document.write( "

Algebra.Com's Answer #841795 by math_helper(2461) $\"\"$ $\"About$

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document.write( "This solution assumes the conventional meaning of width, W, to be the shorter side of the rectangle.  The length, L, is taken to be the longer side.\r
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document.write( "The minimum diagonal of the rectangle will be when L = W = sqrt(12)  (i.e. a square is formed).   However, with these dimensions, the diagonal is only  and that is less than the required 5cm.\r
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document.write( "Recall the 3-4-5 triangle:
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document.write( "If the length is set to 4cm, the width is then 12/4 = 3cm, and we get 
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document.write( "D = diagonal =  as required.\r
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document.write( "Hence,  cm   \r
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document.write( "( The length, L, has bounds  ) \n" );
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