document.write( "Question 115648: Hi!
\n" ); document.write( "I need help with log(x+6)- logx= log(x+2)
\n" ); document.write( "Thanks so much
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Algebra.Com's Answer #84179 by vertciel(183)\"\" \"About 
You can put this solution on YOUR website!
Hello there,\r
\n" ); document.write( "\n" ); document.write( "log(x + 6)- log x = log(x + 2)\r
\n" ); document.write( "\n" ); document.write( "= \"+log%28%28x+%2B+6%29%2Fx%29+=+log%28x+%2B+2%29+\"\r
\n" ); document.write( "\n" ); document.write( "= \"+%28x+%2B+6%29%2Fx+=+x+%2B+2+\"\r
\n" ); document.write( "\n" ); document.write( "= \"+x%28x+%2B+2%29+=+x+%2B+6+\"\r
\n" ); document.write( "\n" ); document.write( "= \"+x%5E2+%2B+x+-+6+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "= \"+%28x+%2B+3%29%28x+-+2%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "x = -3, 2 <-- Discard -3 because logarithms can't be negative.\r
\n" ); document.write( "\n" ); document.write( "x = 2\r
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