document.write( "Question 115648: Hi!
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document.write( "I need help with log(x+6)- logx= log(x+2)
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document.write( "Thanks so much \n" );
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Algebra.Com's Answer #84179 by vertciel(183) ![]() You can put this solution on YOUR website! Hello there,\r \n" ); document.write( "\n" ); document.write( "log(x + 6)- log x = log(x + 2)\r \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( "\n" ); document.write( "x = -3, 2 <-- Discard -3 because logarithms can't be negative.\r \n" ); document.write( "\n" ); document.write( "x = 2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |