document.write( "Question 1205143: X²+y²=2
\n" ); document.write( "X-y=4
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Algebra.Com's Answer #841788 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
X²+y²=2
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\n" ); document.write( "X-y=4 ---> y = x-4
\n" ); document.write( "\"x%5E2+%2B+%28x-4%29%5E2+=+2\"
\n" ); document.write( "\"2x%5E2+-+8x+%2B+14+=+0\"
\n" ); document.write( "\"x%5E2+-+4x+%2B+7+=+0\"
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-4x%2B7+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-4%29%5E2-4%2A1%2A7=-12\".
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\n" ); document.write( " The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -12 is + or - \"sqrt%28+12%29+=+3.46410161513775\".
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\n" ); document.write( " The solution is , or
\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-4%2Ax%2B7+%29\"

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\n" ); document.write( "\"x+=+2+%2B+i%2Asqrt%283%29\"
\n" ); document.write( "\"y+=+-2+%2B+i%2Asqrt%283%29\"
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\n" ); document.write( "\"x+=+2+-+i%2Asqrt%283%29\"
\n" ); document.write( "\"y+=+-2+-+i%2Asqrt%283%29\"\r
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