document.write( "Question 115665: solve the system by addition
\n" ); document.write( "3x - y =1
\n" ); document.write( "3x -y = 2
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Algebra.Com's Answer #84178 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"3%2Ax-1%2Ay=1\"
\n" ); document.write( " \"3%2Ax-1%2Ay=2\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 3 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 3 and 3 is 3, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -1 like this:
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\n" ); document.write( " \"1%2A%283%2Ax-1%2Ay%29=%281%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-1%2A%283%2Ax-1%2Ay%29=%282%29%2A-1\" Multiply the bottom equation (both sides) by -1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"3%2Ax-1%2Ay=1\"
\n" ); document.write( " \"-3%2Ax%2B1%2Ay=-2\"
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\n" ); document.write( " Notice how 3 and -3 and 1 and 1 add to zero (ie \"3%2B-3=0\" \"-1%2B1=0\")
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\n" ); document.write( " However 1 and -2 add to -1 (ie \"1%2B-2=-1\");
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\n" ); document.write( " So we're left with
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\n" ); document.write( " \"0=-1\"
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\n" ); document.write( " which means no value of x or y value will satisfy the system of equations. So there are no solutions
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\n" ); document.write( " So this system is inconsistent
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