document.write( "Question 1205123: A water tower 30 m tall is located at the top of a hill. From a distance of 120 m down the hill it is observed that the angled formed between the top and base of the tower is 8°. Find the angle of inclination of the hill. \n" ); document.write( "

Algebra.Com's Answer #841771 by Edwin McCravy(20054) $\"\"$ $\"About$

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document.write( "Let the tower be CT. It's a very steep hill.\r\n" );
document.write( "The hill is AC. The observer is down at A.\r\n" );
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document.write( "We use the law of sines on triangle ACT\r\n" );
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document.write( "This is the ambiguous case ASS, but since we know θ is acute,\r\n" );
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document.write( "Angle θ and angle BAT are complementary, so\r\n" );
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document.write( "Angle BAT = \r\n" );
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document.write( "So the angle of inclination of the hill is angle BAC\r\n" );
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document.write( "Angle BAC = Angle BAT - 8^o = 56.17263736^o - 8^o = 48.17263736^o.\r\n" );
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document.write( "Edwin

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