document.write( "Question 1205064: There are 12 members on a board of directors. If they must form a subcommittee of members 3, how many different subcommittees are possible? \n" ); document.write( "
Algebra.Com's Answer #841686 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Assuming the 3 subcommittee members don't have titles (i.e. they serve with equal standing and none are distinguishable from each other with respect to the subcommittee):
\n" ); document.write( " C(12,3) = 12!/((12-3)!*3!) = 12!/(9!*3!) = 220
\n" ); document.write( "---
\n" ); document.write( "Aside...
\n" ); document.write( "If there was a \"head of subcommittee\" and \"spokesperson of subcommittee\" then we would not need to divide by the 3! above (similar to \"order matters\") and you'd get:
\n" ); document.write( " P(12,3) = 12!/(12-3)! = 12!/9! = 1320\r
\n" ); document.write( "\n" ); document.write( "Aside #2...
\n" ); document.write( "If, say, exactly one member was 'spokesperson' and the other two were otherwise equal (without title), you'd have:
\n" ); document.write( " 12 * C(11,2) = 12*(11!/(9!*2!)) = 660\r
\n" ); document.write( "\n" ); document.write( "You can see from the pattern, the more distinctions that are made, the greater the number of subcommittees that can be formed. \n" ); document.write( "
\n" );