document.write( "Question 1205049: Find the area of the shaded region.
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Algebra.Com's Answer #841657 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
1. Area of sector - area of triangle = area of shaded portion\r
\n" ); document.write( "\n" ); document.write( "CM = 16* sin 27.5 degrees =7.3879*2=14.775\r
\n" ); document.write( "\n" ); document.write( "OM = 16* cos 27.5 degrees =14.19\r
\n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2 *14.775*14.19=104.828 cm^2\r
\n" ); document.write( "\n" ); document.write( "Area of sector = \"%28%28theta%29%2F360%29%2Api%2Ar%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " = \"%28%2855%29%2F360%29%2Api%2A16%5E2\"=122.87 cm^2\r
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\n" ); document.write( "\n" ); document.write( "122.87-104.828= 18.042 cm^2 approx Area of shaded portion.\r
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\n" ); document.write( "\n" ); document.write( "OR you can directly use the formula given below\r
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\n" ); document.write( "\n" ); document.write( "A = \"%281%2F2%29+%2Ar%5E2%2A+%28%28pi%2A%28theta%29%2F180%29+-sin+%28theta%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "A=5*256*((pi*55/180)-sin55degrees)\r
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