document.write( "Question 1205049: Find the area of the shaded region.
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Algebra.Com's Answer #841657 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 1. Area of sector - area of triangle = area of shaded portion\r \n" ); document.write( "\n" ); document.write( "CM = 16* sin 27.5 degrees =7.3879*2=14.775\r \n" ); document.write( "\n" ); document.write( "OM = 16* cos 27.5 degrees =14.19\r \n" ); document.write( "\n" ); document.write( "Area of triangle = 1/2 *14.775*14.19=104.828 cm^2\r \n" ); document.write( "\n" ); document.write( "Area of sector = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "122.87-104.828= 18.042 cm^2 approx Area of shaded portion.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OR you can directly use the formula given below\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A=5*256*((pi*55/180)-sin55degrees)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |