document.write( "Question 1205030: Given 30-60-90 triangle with sides p\sqrt(6) , p\sqrt(2 ), q\sqrt(3); find p, q
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Algebra.Com's Answer #841640 by ikleyn(52873)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "        Notice that I rewrote the condition using normal designations for the division operation.\r
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document.write( "Two sides  \"p%2Fsqrt%282%29\"  and  \"p%2Fsqrt%286%29\"  have the ratio\r\n" );
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document.write( "    \"%28%28p%2Fsqrt%282%29%29%29%2F%28%28p%2Fsqrt%286%29%29%29\" = \"sqrt%286%29%2Fsqrt%282%29\" = \"sqrt%283%29\".\r\n" );
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document.write( "In combination with the given fact that the triangle is 30-60-90, \r\n" );
document.write( "it means that  \"p%2Fsqrt%286%29\"  is  the shorter leg,  while  \"p%2Fsqrt%282%29\"  is  the longer leg.\r\n" );
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document.write( "    +-----------------------------------------------+\r\n" );
document.write( "    |      It admits only one interpretation,       |\r\n" );
document.write( "    |  and no other interpretation is admittable.   |\r\n" );
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document.write( "Hence, \"q%2Fsqrt%283%29\" is the hypotenuse, and we can write\r\n" );
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document.write( "    \"2%2A%28p%2Fsqrt%286%29%29\" = \"q%2Fsqrt%283%29\"\r\n" );
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document.write( "(the hypotenuse length is twice the shorter leg), since the triangle is 30-60-90.\r\n" );
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document.write( "It gives  q = \"%282%2Ap%2Asqrt%283%29%29%2Fsqrt%286%29\" = \"%282%2Fsqrt%282%29%29%2Ap\" = \"sqrt%282%29%2Ap\".\r\n" );
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document.write( "So, the sides are:  \"p%2Fsqrt%286%29\"  is  the shorter leg,  \"p%2Fsqrt%282%29\"  is  the longer leg and  \"q%2Fsqrt%283%29\" = \"%28sqrt%282%29%2Ap%29%2Fsqrt%283%29\"  is the hypotenuse.\r\n" );
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document.write( "We can write then Pythagorean equation\r\n" );
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document.write( "    \"%28p%2Fsqrt%286%29%29%5E2\" + \"%28p%2Fsqrt%282%29%29%5E2\" = \"%282%2F3%29%2A%28sqrt%282%29%29%5E2%2Ap%5E2\",\r\n" );
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document.write( "or\r\n" );
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document.write( "    \"p%5E2%2F6\" + \"p%5E2%2F2\" = \"%282%2F3%29%2Ap%5E2\",\r\n" );
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document.write( "    \"1%2F6\" + \"3%2F6\" = \"2%2F3\",\r\n" );
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document.write( "    \"4%2F6\" = \"2%2F3\",\r\n" );
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document.write( "    \"2%2F3\" = \"2%2F3\",\r\n" );
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document.write( "which is an identity.\r\n" );
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document.write( "At this point, the problem is solved in full.\r\n" );
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document.write( "ANSWER.  p can be any real positive number; then q = \"sqrt%282%29%2Ap\".  There are infinitely many solutions.\r\n" );
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